manjey73

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Viewing 15 posts - 331 through 345 (of 923 total)
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  • in reply to: Seeking Ways to Give Back for RapidSCADA #15202
    manjey73
    Participant

    This will already be a significant contribution. Plus the purchase of existing paid functionality from the developer.

    in reply to: Seeking Ways to Give Back for RapidSCADA #15200
    manjey73
    Participant

    You can develop drivers, modules, plugins, and Admin extensions, both free and paid, and add them to the Scada app store. Thus, you are making a contribution to the development of the Scada system.

    publish

    documentation_develop

    • This reply was modified 1 year, 8 months ago by manjey73.
    in reply to: Request to Upload RapidSCADA 6.0 Videos to Bilibili #15186
    manjey73
    Participant

    Is it available in China https://dzen.ru ?
    In Russia, because of problems with Youtube, too, many are switching to something else

    It’s probably easier for the developer to overload everything there.

    in reply to: Auto control module not loading #15168
    manjey73
    Participant

    Update the module, this is a bug on version 6.3.0 when using the module from 6.2.1

    in reply to: Integrating 3 colour LED Module #15079
    manjey73
    Participant

    What kind of resources are we talking about?
    If you do not want to use the Auto-Control Module, then you can simply enter the desired number. Or make yourself an enumeration command of several colors

    in reply to: Change default port number 10008 #15073
    manjey73
    Participant

    WEB ports are configured in IIS on Windows or in nginx settings on Linux

    in reply to: Channel Read Bits #15067
    manjey73
    Participant

    Chart Pro falls on the string variable – a white screen 🙂

    in reply to: Channel Read Bits #15066
    manjey73
    Participant

    Something is not working to display the number in binary form. It shows !!! on the graph, in the table ---

    in reply to: Channel Read Bits #15063
    manjey73
    Participant

    Oops, I didn’t know there was a binary display format 🙂

    You need to add option B for the format and test it.
    Auxiliary Tables – Formats

    Custom Formats

    • This reply was modified 1 year, 8 months ago by manjey73.
    • This reply was modified 1 year, 8 months ago by manjey73.
    in reply to: Channel Read Bits #15052
    manjey73
    Participant

    Format Channel – String
    Data Type = ASCII

    public string BitsView(double number)
    {
    byte[] data = BitConverter.GetBytes(Convert.ToUInt16(number));
    uint N = BitConverter.ToUInt16(data, 0);
    string bits = Convert.ToString(N, 2);
    return bits;
    }

    Make a calculation channel with the specified parameters. Use the specified formula. Displaying a string in the channel, but only for a byte. In order for the whole number to be displayed correctly, the formula needs to be refined.

    in reply to: Channel Read Bits #15051
    manjey73
    Participant

    00000010 is a binary display of bits of a number, I don’t even know if there is support for such a display in the system. I wrote some kind of formula for this and displayed it as a string

    in reply to: Channel Read Bits #15049
    manjey73
    Participant

    Set the HEX format in the channel, perhaps this will be enough for you.

    There is a choice there

    Hexadecimal
    Hexadecimal 2 digits
    Hexadecimal 4 digits
    Hexadecimal 8 digits

    • This reply was modified 1 year, 8 months ago by manjey73.
    in reply to: Channel Read Bits #15047
    manjey73
    Participant

    00000010 in the bit representation is the number 2 in the decimal representation. Do you need to see the number in some other format?

    in reply to: Channel Read Bits #15045
    manjey73
    Participant

    GetAnyBits(Val(1080), 3, 7)
    Val(XXX) – Where is the XXX number of your channel

    00000111 is the number 7 in the bit representation
    When you need to select 3 bits in a value, you need to make a logical AND with the bits you need, and depending on which bits from the beginning you want to compare, you need to shift the bits you need so that they turn out to be starting from the zero bit

    00001111 is the number 15, which will correspond to four consecutive bits

    00000011 is the number 3, which will correspond to two consecutive bits

    01010110 – Your certain number for checking 3 bits. You need to shift this representation to position 0 (n = 2) 00010101 and make AND with the number 7 (00000111)

    in reply to: Channel Read Bits #15042
    manjey73
    Participant

    00111000

    The 0th bit is on the right. You need to shift by 3

    GetAnyBits(Val(XXX), 3, 7) like this

    • This reply was modified 1 year, 8 months ago by manjey73.
Viewing 15 posts - 331 through 345 (of 923 total)