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manjey73Participantwhen you use the Off-On enumeration and the command window has two corresponding buttons, a 0 or 1 is sent to your command as a double. Based on this, it is required to build a formula.
manjey73Participantpublic double exsamp()
{
if (Cmd==0) return 0;
elseif (Cmd==1) return 65 280;
else return double.NaN;
}there is no On or OFF in Cmd, numeric values are there, even if you use enumerations.
manjey73Participantit may not be possible to embed mim in mim. Try FacePlate
manjey73ParticipantNow it’s clear, is there a problem with transferring channels if one *.mim is embedded in another?
Is it possible to embed mim directly into mim? it seems that FacePlate and their exported properties are used for this.
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This reply was modified 3 months, 1 week ago by
manjey73.
manjey73Participantno matter how many times I used the parser, I always focused on the fact that CRC = OK, and I didn’t even pay attention to the value itself. 🙂
manjey73ParticipantWell, @Mikhail can easily see his mistake. It is enough to look at the result of the CRC calculation in the Modbus driver before it is split into bytes for the packet 🙂
manjey73Participantdid I understand correctly that when you remove frames from the mnemonic scheme, then the trend component starts working for you?
manjey73Participantyou probably made a mistake with the channel number on the trend.
manjey73ParticipantIt is allowed to link to html in another resource, for example http://10.2.0.1:8081 but in this case, the javascript of another resource may be blocked inside the frame.
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This reply was modified 3 months, 1 week ago by
manjey73.
manjey73Participanthttp://localhost:5000/Object_13 What do you have there? the link for the frame?
if I’m not mistaken, you need to place your pages in wwwroot\custom and the link will start with /custom/myHtmlPage.html
Do you want to download the svg directly as a link? I’m not sure that’s going to happen.
You have Images in the project tree, so you should add an image there. Or a more complicated way, use the ExtraMarkup component.
manjey73ParticipantEnter there 10 06 02 02 00 03
And then enter 10 06 02 02 00 03 F2 6A if the byte order in the CRC corresponded to the display of the VALUE in the parser
manjey73Participantthe calculation is correct, but the displayed value is incorrect, since the CRC in Modbus is always inserted the lowest byte ahead.
manjey73ParticipantCheck in the browser (show code) on the i-frame element
manjey73Participant
manjey73ParticipantIn Modbus, the lowest CRC byte always goes first, then the highest.
A feature of the CRC calculation in the Modbus protocol is that if we send a packet along with the CRC to the calculation, we should get 0 -
This reply was modified 3 months, 1 week ago by
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