Accessing Schneider PM810MG via Modbus RTU

[kumajaya]

Device template:

<?xml version="1.0" encoding="utf-8"?>
<DevTemplate>
  <Settings>
    <ZeroAddr>true</ZeroAddr>
    <DecAddr>true</DecAddr>
    <DefByteOrder2 />
    <DefByteOrder4 />
    <DefByteOrder8 />
  </Settings>
  <ElemGroups>
    <ElemGroup active="true" tableType="InputRegisters" address="1104" name="Current">
      <Elem name="Average Current" type="ushort" byteOrder="" />
    </ElemGroup>
    <ElemGroup active="true" tableType="InputRegisters" address="1122" name="Voltage LL">
      <Elem name="Average Voltage LL" type="ushort" byteOrder="" />
    </ElemGroup>
    <ElemGroup active="true" tableType="InputRegisters" address="1127" name="Voltage LN">
      <Elem name="Average Voltage LN" type="ushort" byteOrder="" />
    </ElemGroup>
    <ElemGroup active="true" tableType="InputRegisters" address="1142" name="Power">
      <Elem name="Total Power" type="ushort" byteOrder="" />
    </ElemGroup>
    <ElemGroup active="true" tableType="InputRegisters" address="1179" name="Frequency">
      <Elem name="Frequency" type="ushort" byteOrder="" />
    </ElemGroup>
    <ElemGroup active="true" tableType="InputRegisters" address="1699" name="Energy">
      <Elem name="Energy" type="ulong" byteOrder="67452301" />
    </ElemGroup>
  </ElemGroups>
  <Cmds />
</DevTemplate>

Formula to convert energy register based on https://www.se.com/id/en/faqs/FA212766/ info:
double Mod10(double val) {
ulong v = Convert.ToUInt64(val);
return ((v >> 48) * 1000000000000) + (((v >> 32) & 0xFFFF) * 100000000) + (((v >> 16) & 0xFFFF) * 10000) + (v & 0xFFFF);
}

@Mikhail Am I doing right? Or is there a better solution?

[Mikhail]

Who are crazy authors of such algorithms…

Please scroll down this Russian version the article, there is a formula:

double Convert(double x)
{
    return x<32768 ? x*760/32767 : -(double)(ushort)(~(ushort)x|128+1)*210/9182;
}

May be it can be example.
To be honest, I didn’t understand Mod10 calculations. If you change your question to something more specific, what calculation do you need, I’ll try to help.

[Author]

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